\(Fx\ 50\cos60=25N\)
\(Fy\ 50\sin60=43.5N\)
\(100+200\cos45+100=341.4mm\ \ \ .3414m\)
\(200\cos45=141.4mm\ \ .1414m\)

Step 2.- Calculate the moment

\(\vec{M_o}\ -\left(43.5N\right)\left(-3414m\right)+\left(25N\right)\left(.1414m\right)=-11.2Nm\)