\(S=\frac{PL}{AE}\)
\(\Sigma FY=0\)
\(FA+FB-60KN=0\)
\(\Sigma MO=0\)
\(FB=\frac{120kNm}{6m}=20kN\)
\(SA=\frac{\left(-40X^{-3}\ N\right)\left(2m\right)}{2\left(10^{-3}\right)m^2\ \left(6X10^{10}\right)}=\ -666X10^6\)
\(SB=\frac{\left(20X10^3N\right)\left(3m\right)}{2\left(10^{-3}\right)m^2\left(6X10^{10}\right)}=500X^6=0,5\ mm\)