\(\Sigma Fy=0\)
\(Fy-w=0\)
\(Fy=w\)
\(F\sin\theta=mg\)
\(Fy=F\sin\theta\)
\(F\sin60=1000\left(\sin60\right)=866\ N\)
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El problema nos pide la componente vertical de la tension de la figura podemos observar que la componente vertical es Fy.
A partir del triangulo sabemos que: Fy= F sin \(\theta\).
Por lo tanto sustituir F=1000 N y \(\theta\) =60° y obtener la solución Fy= (1000 N) (sin 60)
Problem 4. After its most recent delivery, the infamous stork announces the good news. If the sign has a mass of 10 kg, then what is the tensional force in each cable? Use trigonometric functions and a sketch to assist in the solution.