\(Fy=F\sin\theta\)Solución:
\(Fy=F\sin\theta\)
\(Fy=F\sinθ=F\sin60°=(1000)\sin60=866N\)
El problema nos pide la componente vertical de la tension de la figura podemos observar que la componente vertical es Fy.
A partir del triangulo sabemos que: Fy= F sin \(\theta\).
Por lo tanto sustituir F=1000 N y \(\theta\) =60° y obtener la solución Fy= (1000 N) (sin 60)
Problem 4. After its most recent delivery, the infamous stork announces the good news. If the sign has a mass of 10 kg, then what is the tensional force in each cable? Use trigonometric functions and a sketch to assist in the solution.