Consider the tow truck below. If the tensional force in the cable is 1000 N and if the cable makes a 60-degree angle with the horizontal, then what is the vertical component of force that lifts the car off the ground?

Datos

\(F_x=1000N\)
\(\theta=60\)

Fórmula 

\(F_y=F\ sen\ \theta\)

Desarrollo

\(F_y=866.025N\)