SEN\(\theta\) = 3/5
COS\(\theta\)= 4/5
TAN\(\theta\)= 3/4
FAX= FA cos\(\theta\) = 4/5 FA
FAY= FA SEN\(\theta\) = 3/5
FBX= FB COS 60
FBY-FB SEN 60
\(\Sigma\) FX = 0
-FBX- FAY= 0
- 30lb cos 60 - 4/5 FA=0
4/5 FA= - 30 lb
FA= 4/5(-30lb cos 60)
FA= 18.75
Para B
rBx= 6ft ; FBx = 30 lb COS 60°
By= 0; FBy= 30 lb sen 60°
MA = RAx FAy - rAy=(9ft)(3/5)-(0)(4/5 FA)= 27/5 lb*ft
Para A
rAx = 9ft; FAx= 4/5 FA
FAy= 0; FAy= 3/5 FA
MB= rBx  Fby- rBy  FBx= (6ft)( 30 lb sen 60°)- (0) ( 30 lb cos 60°)= 155.88 lb/ft
\(\Sigma\)M= 0
MB= MA =0
27/5 FA= 155.88
FA= 155.88/(27/5)
FA= 28.86