SENθ = 3/5 
COSθ= 4/5
TANθ= 3/4
FAx= FA cos θ = 4/5 FA
FBy   FAY= FA SENθ = 3/5
FBx = FB COS 60
FBy -FB SEN 60  
ΣFx = 0  
-FBx - FAy= 0  
- 30 libras cos 60 - 4/5 FA=0  
4/5 FA= - 30 libras
FA= 4/5(-30 libras cos 60) = 18.75
  Para B
rBx= 6 ft  FBx = 30 libras  COS 60°  
By= 0  FBy= 30 libras sen 60°  
M A = RA x  FAy - rAy = (9 pies) (3/5) - (0) (4/5 FA)= 27/5 libas * pies     
Para A
rAx = 9 pies  FAx= 4/5 FA  
FAy= 0  FAy= 3/5 FA  
M B = rBx  Fby - rBy FBx = (6 pies) ( 30 libras sen 60°)- (0) ( 30 libras  cos  60°)= 155.88 libras/pies
    
  ΣM= 0 M B= MA =0
27/5 FA = 155.88
FA = 155.88/ (27/5)   = 28.86