SENθ = 3/5
COSθ= 4/5
TANθ= 3/4
FAx= FA cos θ = 4/5 FA
FBy FAY= FA SENθ = 3/5
FBx = FB COS 60
FBy -FB SEN 60
ΣFx = 0
-FBx - FAy= 0
- 30 libras cos 60 - 4/5 FA=0
4/5 FA= - 30 libras
FA= 4/5(-30 libras cos 60) = 18.75
Para B
rBx= 6 ft FBx = 30 libras COS 60°
By= 0 FBy= 30 libras sen 60°
M A = RA x FAy - rAy = (9 pies) (3/5) - (0) (4/5 FA)= 27/5 libas * pies
Para A
rAx = 9 pies FAx= 4/5 FA
FAy= 0 FAy= 3/5 FA
M B = rBx Fby - rBy FBx = (6 pies) ( 30 libras sen 60°)- (0) ( 30 libras cos 60°)= 155.88 libras/pies
ΣM= 0 M B= MA =0
27/5 FA = 155.88
FA = 155.88/ (27/5) = 28.86