Solución.-

\(\)\(ry=0\)
\(Fy=0\)
\(rx=30Sin60\left(6\right)\)
\(Fx=\left(-\frac{3}{5}\right)\left(9\right)\)
\(Mo=\left(rxFy-rxFx\right)\)
\(Mo=0\left(30Sin60\left(6\right)\right)-0\left(-\frac{3}{5}\right)\left(9\right)\)
\(Mo=155.884+FA5.4\)
\(FA=\frac{155.884}{5.4}\)
\(FA=28.86lb\)