Solución.
\(ry=0\)
\(fy=0\)
\(rx=30Sin60\left(6\right)\)
\(Fx=\left(-\frac{3}{5}\right)\left(Y\right)\)
\(M_{o=}\left(rxFy-ryFy\right)\)
\(M_o=0\left(30\sin60\left(60\right)\right)-0\left(\frac{3}{5}\right)\left(9\right)\)
\(M_o=155884+FA\ 5.4\)
\(FA=\frac{155.884}{5.4}\)
\(FA=28.86\ lb\)