\(q1=\ 4\ e\)
\(q2=e\)
\(r=4x10^{-15\ }m\)
\(e=1.602x10^{-19}\)
\(\frac{\left(\left(4E4x26x11.602x10\left(-\right)19\right)^2\right)}{\left(4.0x10\left(-\right)15\right)^{^2}}\ \ \ \ \ \ \ =14.43N\)