Solución:
Utilizamos la ley de Coulomb:
F 32= K \(\frac{Q3\ Q2}{r_{32}^{2_{ }}}\) = 9x109 \(\frac{Nm2}{C^2}\) \(\frac{\left(65X10^{-6}\ C\right)\left(50X10^{-6\ }C\right)}{\left(0.3m^2\right)}\)
= 325 N
F 31= K \(\frac{Q3\ Q1}{r_{32}^{2_{ }}}\) = 9x109 \(\frac{Nm2}{C^2}\) \(\frac{\left(65X10^{-6}\right)\left(-86X\ 10^{-6}\right)}{\left(0.6m\right)^2}\)
= -139.75 N