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\begin{document}

\title{Informe de soluci\selectlanguage{ngerman}ón de problemas sobre el momento de una fuerza~~~~\selectlanguage{spanish}}



\author[1]{Jordan Israel Garcia Salazar }%
\affil[1]{Instituto Tecnológico Superior Zacatecas Occidente}%


\vspace{-1em}



  
  \date{May 08, 2024}


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\subsection*{Problema 1}

{\label{912031}}\selectlanguage{spanish}
\begin{figure}[H]
\begin{center}
\includegraphics[width=0.42\columnwidth]{figures/problema-1/problema-1}
\caption{{This is a caption
{\label{852249}}%
}}
\end{center}
\end{figure}

Para que la distancia quede recta, en este caso giramos la figura
30\textsuperscript{o}~ en direcci\selectlanguage{ngerman}ón a las manecillas del reloj y para
que éste cambio no afecte al problema original sumaremos los grados~ ~ ~
~ ~ (30\textsuperscript{o}+20\textsuperscript{o~}=
50\textsuperscript{o})

r\textsubscript{x}= 5 ft~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~F\textsubscript{x~}=
- 600N cos 50\textsuperscript{o}

r\textsubscript{y~}= 0.5 ft~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ F\textsubscript{y} =
600N sen 50\textsuperscript{o}~

\(\vec{M}_o\)= {[}(5 ft)(600 sen 50\textsuperscript{o}) - (0.5
ft)(- 600 cos 50\textsuperscript{o}){]}

\(\vec{M}_o\) = 600 sen 50\textsuperscript{o~}(5) + 600 cos
50\textsuperscript{o} (0.5)

\(\vec{M}_o\) = 2490.96 lb.ft

\par\null\par\null

\subsection*{Problema 2}

{\label{561192}}\selectlanguage{spanish}
\begin{figure}[H]
\begin{center}
\includegraphics[width=0.42\columnwidth]{figures/problema-2/problema-2}
\caption{{This is a caption
{\label{190386}}%
}}
\end{center}
\end{figure}

r\textsubscript{x}= 3 + 3m cos 45\textsuperscript{o}~ ~ ~ ~ ~ ~ ~ ~ ~ ~
~ ~ ~ F\textsubscript{x~}= 500N cos 40\textsuperscript{o}

r\textsubscript{y~}= 3m sen 45\textsuperscript{o}~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
~ ~~ F\textsubscript{y} = 500N sen 45\textsuperscript{o}~

\(\vec{M}\) = {[}(3 + 3 cos 45\textsuperscript{o})(500 sen
45\textsuperscript{o}) - (3 sen 45\textsuperscript{o})(500 cos
45\textsuperscript{o}){]}

\(\vec{M}\) = 1060.66 Nm

\par\null

\subsection*{Problema 3}

{\label{182053}}\par\null\selectlanguage{spanish}
\begin{figure}[H]
\begin{center}
\includegraphics[width=0.42\columnwidth]{figures/problema-3/problema-3}
\caption{{This is a caption
{\label{755689}}%
}}
\end{center}
\end{figure}

F\textsubscript{r} = F\textsubscript{1} + F\textsubscript{2} = 100-200,~
-120+250, 75+100

F\textsubscript{r} = -100i + 130j +175k~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~

r\textsubscript{oA} = 4i + 5j + 3k

~\(\vec{M}\) = (5)(175) - (3)(130), (3)(-100) - (4)(175),
(4)(130) - (5)(-100)

\(\vec{M}\) = 485i - 1000j +1020k~ ~ lb.ft

\selectlanguage{spanish}
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